Summary

The general term of a *geometric sequence* is given by $T_{n}=ar^{n-1}$. Here:

- $a$ is called the first term;
- $r$ is called the common ratio;
- $n$ is the number of terms;
- $T_{n}$ is the nth term.

Class exercises

- Consider a degenerate case in which the common ratio of a geometric sequence is $1$. Describe the general appearance of the geometric sequence in this case.
- Explain why
*zero*is not allowed to be one of the terms in a geometric sequence. - Identify the first term and the common ratio of each geometric sequence:
- $-2,4,-8,16,-32,\cdots$
- $\frac{-1}{4},\frac{1}{12},\frac{-1}{36},\frac{1}{108},\frac{-1}{324},\cdots$
- $0.8,2.4,7.2,21.6,64.8,\cdots$

- The first term of a geometric sequence is $7$, while the common ratio is $5$. Find the $10$th term of the sequence.
- Find the number of terms in the sequence $2,-6,18,-54,\cdots,39366$.
- Insert
*five*geometric means between $3$ and $192$. That is, find numbers $a,b,c,d,e$ for which the sequence $3,a,b,c,d,e,192$ would be geometric. - Let $x\neq -1,0$ be a real number.
**PROVE**that the 3-term sequence $$1,~(x+1),~(x^2+2x+1)$$ is geometric. - Let $x,y$ be non-zero real numbers.
**PROVE**that the enumeration $$2x,~x+y,~y$$*cannot*be geometric. - Let $a,b,c,d\neq 0$.
**PROVE**that if the sequence $a,~b,~c,~d$ is geometric, then $(b+c)^2=b(c+d)+c(a+b)$. - Let $a,b,c\neq 0$.
**PROVE**that the quadratic equation $ax^2+bx+c=0$ has only*one*root if, and only if, the sequence $2a,~b,~2c$ is geometric.